a quadratic generalisation
links with the difference between consecutive cubes
and this is no coincidence (see here)
this general form is also
n^3 - (n - 1)^3
summing the terms always gives a cube number
(e.g. 1 + 7 + 19 + 37 = 64 = 4^3)
n = 4
n = 5
n = 6
n = 8
centred hexagonal numbers are closely related to triangular numbers:
No comments:
Post a Comment